H\u00f4m nay ch\u00fang t\u00f4i xin chia s\u1ebb \u0111\u1ebfn c\u00e1c b\u1ea1n nh\u1eefng c\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 l\u00e3i g\u1ea5p 4 l\u1ea7n v\u1ed1n. <\/strong>C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 trong b\u00e0i vi\u1ebft n\u00e0y c\u1ef1c k\u1ef3 hi\u1ec7u qu\u1ea3 v\u00e0 ch\u00ednh x\u00e1c. V\u00ec th\u1ebf n\u1ebfu nh\u01b0 anh em m\u00e0 b\u1ecf l\u1ee1 m\u1ea5t nh\u1eefng chia s\u1ebb do chuy\u00ean gia l\u00f4 \u0111\u1ec1 \u0111\u01b0a ra d\u01b0\u1edbi \u0111\u00e2y s\u1ebd r\u1ea5t \u0111\u00e1ng ti\u1ebfc \u0111\u1ea5y!<\/p>\n Khi n\u00e0o th\u00ec anh em m\u1edbi n\u00ean s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u1ec3 soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 ch\u00ednh x\u00e1c 100%? C\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1 n\u00e0y, n\u00f3 d\u1ef1a theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t trong 2 ng\u00e0y li\u00ean ti\u1ebfp \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y th\u1ee9 3. H\u00e3y c\u00f9ng ch\u00fang t\u00f4i \u0111i t\u00ecm hi\u1ec3u qua v\u00ed d\u1ee5 th\u1ef1c th\u1ebf nh\u00e9!<\/p>\n V\u00ed d\u1ee5: Trong ng\u00e0y th\u1ee9 nh\u1ea5t c\u00f3 \u0111\u1ec1 v\u1ec1 l\u00e0 AB, \u0111\u1ebfn ng\u00e0y th\u1ee9 hai l\u00e0 CD.<\/p>\n X\u00e9t t\u1ed5ng s\u1ed1 \u0111\u1ec1 c\u00f3 trong ng\u00e0y th\u1ee9 nh\u1ea5t c\u00f3: M b\u1eb1ng A + B.<\/p>\n V\u00e0 s\u1ed1 \u0111\u1ec1 trong ng\u00e0y th\u1ee9 hai ch\u00ednh c\u00f3: C + D b\u1eb1ng N.<\/p>\n Sau \u0111\u00f3 b\u1ea1n h\u00e3y x\u00e9t 4 tr\u01b0\u1eddng h\u1ee3p d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 soi c\u1ea7u l\u00f4, t\u00ednh c\u1ea7u \u0111\u1ec1 ch\u00ednh x\u00e1c:<\/p>\n Ngo\u00e0i ra b\u1ea1n c\u1ea7n ph\u1ea3i l\u01b0u \u00fd khi t\u1ed5ng M + N b\u1eb1ng 10 ho\u1eb7c 0. Th\u00ec khi \u0111\u00f3 X c\u00f9ng v\u1edbi Y s\u1ebd \u0111\u1ec1u l\u00e0 0 h\u1ebft.<\/p>\n \u0110\u00e2y l\u00e0 c\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 l\u00e3i g\u1ea5p 4 l\u1ea7n v\u1ed1n <\/strong>b\u1ea1n kh\u00f4ng n\u00ean b\u1ecf qua. Ch\u1eb3ng h\u1ea1n nh\u01b0 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 nhi\u1ec1u nh\u1ea5t l\u00e0 2 c\u1eb7p s\u1ed1 32 ho\u1eb7c l\u00e0 12.<\/p>\n Khi \u0111\u00f3 ch\u1eafc ch\u1eafn \u0111\u1ebfn ng\u00e0y h\u00f4m sau s\u1ed1 l\u00f4 s\u1ebd xu\u1ea5t hi\u1ec7n \u00a0g\u1ed3m c\u00e1c c\u1eb7p l\u00e0 7, 2 v\u00e0 1. Ch\u00fang ta c\u00f3 c\u00e1c c\u1eb7p s\u1ed1 l\u00e0 12, 21, 71, 17 v\u00e0 27, 72, 22, 11,77.<\/p>\n T\u1ed5ng c\u1ed9ng ch\u00fang g\u1ed3m c\u00f3 9 con l\u00f4. Anh em c\u00f3 th\u1ec3 \u0111\u00e1nh m\u1ed9t d\u00e0n 9 l\u00f4. Ho\u1eb7c c\u0169ng c\u00f3 th\u1ec3 c\u0103n c\u1ee9 v\u00e0o nh\u1eefng th\u1ed1ng k\u00ea \u0111\u1ec3 l\u1ecdc ra \u0111\u01b0\u1ee3c nh\u1eefng con l\u00f4 n\u00ean \u0111\u00e1nh.<\/p>\n Anh em c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng c\u1ea7u \u0111\u1ec1 k\u1ebf ti\u1ebfp c\u1ee7a nh\u1eefng ng\u00e0y \u00e2m. Ch\u1eb3ng h\u1ea1n nh\u01b0 n\u1ebfu h\u00f4m nay v\u1ec1 s\u1ed1 n\u00e0y th\u00ec ch\u1eafc ch\u1eafn ng\u00e0y mai n\u00f3 s\u1ebd v\u1ec1 con s\u1ed1 k\u1ebf ti\u1ebfp s\u1ed1 \u0111\u00f3.<\/p>\n C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 l\u00e3i g\u1ea5p 4 l\u1ea7n v\u1ed1n <\/strong>n\u00e0y d\u00f9ng cho t\u1ea5t c\u1ea3 m\u1ecdi con s\u1ed1 k\u1eb9p \u1edf c\u00e1c gi\u1ea3i. Th\u00f4ng th\u01b0\u1eddng trong 1 b\u1ea3ng k\u1ebft qu\u1ea3 s\u1ebd xu\u1ea5t hi\u1ec7n r\u1ea5t nhi\u1ec1u d\u1ea1ng k\u1eb9p s\u1ed1 kh\u00e1c nhau.<\/p>\n V\u00ec v\u1eady anh em h\u00e3y \u0111\u1ec3 \u00fd n\u1ebfu th\u1ea5y con n\u00e0o m\u00e0 k\u1eb9p gi\u1eefa hai s\u1ed1 0 ho\u1eb7c l\u00e0 gi\u1eefa hai s\u1ed1 1. Khi \u0111\u00f3 b\u1ea1n h\u00e3y \u0111\u00e1nh c\u1eb7p s\u1ed1 \u0111\u00f3 li\u00ean ti\u1ebfp trong 3 ng\u00e0y. Ch\u1eafc ch\u1eafn n\u00f3 s\u1ebd v\u1ec1 v\u00e0 th\u01b0\u1eddng th\u00ec \u0111\u1ebfn ng\u00e0y th\u1ee9 2 l\u00e0 n\u00f3 \u0111\u00e3 v\u1ec1.<\/p>\n B\u00f3ng s\u1ed1 c\u1ee7a c\u1ea7u l\u00f4 \u0111\u1ec3 s\u1ebd c\u00f3 2 lo\u1ea1i l\u00e0 b\u00f3ng D\u01b0\u01a1ng v\u00e0 \u00c2m. B\u00f3ng D\u01b0\u01a1ng g\u1ed3m nh\u1eefng s\u1ed1: 0 \u2013 5, 2 \u2013 7, 1 \u2013 6, 3 \u2013 8, 4 \u2013 9 v\u00e0 5 \u2013 0, 7 \u2013 2, 6 \u2013 1, 8 \u2013 3, 9 \u2013 4. C\u00f2n b\u00f3ng \u00c2m l\u00e0 nh\u1eefng s\u1ed1: 7 \u2013 0, 4 \u2013 1, 9 \u2013 2, 6 \u2013 3, 8 \u2013 5, v\u00e0 0 \u2013 7, 1 \u2013 4, 2 \u2013 9, 3 \u2013 6, 5 \u2013 8.<\/p>\n V\u1edbi c\u1ea7u b\u00f3ng n\u00e0y b\u1ea1n h\u00e3y theo d\u00f5i xem: N\u1ebfu nh\u01b0 l\u00f4 h\u00f4m nay v\u1ec1 m\u00e0 c\u00f3 b\u00f3ng c\u1ee7a \u0111\u1ec1 ng\u00e0y h\u00f4m qua. Khi \u0111\u00f3 b\u1ea1n h\u00e3y ti\u1ebfp t\u1ee5c d\u00f9ng b\u00f3ng c\u1ee7a \u0111\u1ec1 h\u00f4m nay \u0111\u1ec3 \u0111\u00e1nh l\u00f4 cho ng\u00e0y mai. \u0110\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 c\u00f3 \u0111\u1ed9 ch\u00ednh x\u00e1c c\u1ef1c cao.<\/p>\n V\u1edbi c\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 n\u00e0y b\u1ea1n h\u00e3y l\u01b0u \u00fd \u0111\u1ebfn gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 2 v\u00e0 th\u1ee9 3. Sau \u0111\u00f3 b\u1ea1n h\u00e3y gh\u00e9p s\u1ed1 \u0111\u1ea7u ti\u00ean trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y th\u1ee9 2 v\u1edbi s\u1ed1 \u0111\u1ea7u ti\u00ean trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y th\u1ee9 3. V\u00e0 c\u1ed9ng hai s\u1ed1 \u0111\u00f3 l\u1ea1i v\u1edbi nhau v\u00e0 nu\u00f4i d\u00e0n t\u1ed5ng n\u00e0y trong 5 ng\u00e0y cu\u1ed1i tu\u1ea7n.<\/p>\n Nh\u1eefng con l\u00f4 d\u1ec5 tr\u00fang nh\u1ea5t ch\u00ednh l\u00e0 c\u00e1c con m\u00e0 c\u00f3 t\u1ea7n su\u1ea5t ra cao nh\u1ea5t trong th\u00e1ng. V\u00ec v\u1eady anh em h\u00e3y th\u1ed1ng k\u00ea v\u00e0 n\u00ean ch\u1ecdn nh\u1eefng c\u1eb7p n\u00e0y \u0111\u1ec3 \u0111\u00e1nh. Tuy nhi\u00ean b\u1ea1n c\u1ea7n ph\u1ea3i l\u01b0u \u00fd tr\u00e1nh nh\u1eefng con l\u00f4 m\u00e0 l\u00e2u ng\u00e0y kh\u00f4ng ra (l\u00f4 gan). B\u1edfi v\u00ec nh\u1eefng con s\u1ed1 n\u00e0y th\u01b0\u1eddng s\u1ebd c\u00f3 t\u1ec9 l\u1ec7 n\u1ed5 c\u1ef1c th\u1ea5p.<\/p>\n L\u00f4 b\u1ecb l\u1ed9n ngh\u0129a l\u00e0 g\u00ec? Ch\u1eb3ng h\u1ea1n nh\u01b0 b\u1ea1n \u0111\u00e1nh 23, th\u1ebf nh\u01b0ng n\u00f3 l\u1ea1i v\u1ec1 32. Ho\u1eb7c b\u1ea1n \u0111\u00e1nh 52, th\u1ebf nh\u01b0ng n\u00f3 l\u1ea1i v\u1ec1 25 nh\u1eefng 2 nh\u00e1y. V\u1edbi c\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 n\u00e0y b\u1ea1n c\u1ea7n l\u01b0u \u00fd:<\/p>\n <\/main><\/p>\nNguy\u00ean l\u00fd <\/strong>soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 <\/strong>ch\u00ednh x\u00e1c 100%<\/strong><\/h2>\n
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C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/strong><\/h3>\n
C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 theo ng\u00e0y \u00e2m<\/strong><\/h3>\n
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C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 theo c\u1ea7u k\u1eb9p s\u1ed1 <\/strong><\/h3>\n
C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 theo c\u1ea7u b\u00f3ng<\/strong><\/h3>\n
C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 nu\u00f4i trong 5 ng\u00e0y<\/strong><\/h3>\n
C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 b\u1eaft c\u00e1c con lo c\u00f3 t\u1ea7n s\u1ed1 ra nhi\u1ec1u nh\u1ea5t \u1edf trong th\u00e1ng<\/strong><\/h3>\n
C\u00e1ch soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 b\u1eaft nh\u1eefng con l\u00f4 b\u1ecb l\u1ed9n<\/strong><\/h3>\n
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C\u1ea6U V\u00cdP MI\u1ec0N B\u1eaeC T\u1eea CHUY\u00caN GIA<\/span><\/h3>\n